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Question
The first term of an A.P. is 5, the common difference is 3 and the last term is 80;
Solution
In the given problem, we are given an A.P whose,
First term (a) = 5
Last term (`a_n`) = 80
Common difference (d) = 3
We need to find the number of terms present in it (n)
So here we will find the value of n using the formula, `a_n = a + (n - 1)d`
So, substituting the values in the above-mentioned formula
80 = 5 + (n - 1)3
80 - 5 = 3n - 3
75 + 3 = 3n
`n = 78/3`
n = 26
Thus n = 26
Therefore, the number of terms present in the given A.P is 26
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