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Question
If k + 2, 4k – 6 and 3k – 2 are three consecutive terms of an A.P., then the value of k is ______.
Options
3
–3
4
–4
Solution
If k + 2, 4k – 6 and 3k – 2 are three consecutive terms of an A.P., then the value of k is 3.
Explanation:
Given k + 2, 4k – 6 and 3k – 2 are three consecutive terms of an A.P.
Then (4k – 6) – (k + 2) = (3k – 2) – (4k – 6)
3k – 8 = – k + 4
4k = 8 + 4 = 12
k = `12/4` = 3
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