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Question
The following table shows the daily wages of workers in a factory:
Daily wages in (Rs) | 0 – 100 | 100 – 200 | 200 – 300 | 300 – 400 | 400 – 500 |
Number of workers | 40 | 32 | 48 | 22 | 8 |
Find the median daily wage income of the workers.
Solution
Class | Frequency (f) | Cumulative Frequency (cf) |
0 – 100 | 40 | 40 |
100 – 200 | 32 | 72 |
200 – 300 | 48 | 120 |
300 – 400 | 22 | 142 |
400 – 500 | 8 | 150 |
N = Σ𝑓 = 150 |
Now, N = 150
`⇒ N/2` = 75.
The cumulative frequency just greater than 75 is 120 and the corresponding class is 200 – 300.
Thus, the median class is 200 – 300.
∴ l = 200, h = 100, f = 48, cf = c.f. of preceding class = 72 and `N/2` = 75.
Now,
Median, M = `l + {h×((N/2−cf)/f)}`
`= 200 + {100 × ((75 − 72)/48)}`
= 200 + 6.25
= 206.25
Hence, the median daily wage income of the workers is Rs 206.25.
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