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The frequency distribution table shows the number of mango trees in a grove and their yield of mangoes. Find the median of data. - Algebra

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Question

The frequency distribution table shows the number of mango trees in a grove and their yield of mangoes. Find the median of data.

No. of Mangoes 50 - 100 100 - 150 150 - 200 200 - 250 250 - 300
No. of trees 33 30 90 80 17
 
Sum

Solution

Class (Number of
working hours)
Frequency
(Number of
workers)
Cumulative frequency 
less than the
upper limit
50 - 100 33 33
100 - 150  30 63
150 - 200
(Median Class)
90 153
200 - 250 80 233
250 - 300 17 250
  N = 250  

From the above table, we get

L (Lower class limit of the median class) = 150

N (Sum of frequencies) = 250

h (Class interval of the median class) = 50

f (Frequency of the median class) = 90

cf (Cumulative frequency of the class preceding the median class) = 63

Now, Median = `L + ((N/2 - cf)/f) xx h`

= `150 + ((250/2 - 63)/90) xx 50`

= `150 + ((125 - 63)/90) xx 50`

= `150 + (62/9) xx 5`

= `150 + 310/9`

= 150 + 34.44

= 184.44 mangoes

= 184 mangoes

Hence, the median of data is 184 mangoes.

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Chapter 6: Statistics - Practice Set 6.2 [Page 145]

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