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Karnataka Board PUCPUC Science Class 11

The Friction Coefficient Between the Board and the Floor Shown in the Following Figure is μ - Physics

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Question

The friction coefficient between the board and the floor shown in the following figure is μ. Find the maximum force that the man can exert on the rope so that the board does not slip on the floor.

One Word/Term Answer
Sum

Solution

Let T be the maximum force exerted by the man on the rope.

From the free body diagram,
R + T = Mg
⇒ R = Mg − T                     (1)
Again,
R1 − R − mg = 0
⇒ R1 = R + mg                   (2)
and
T − μR1 = 0

From Equation (2),
T − μ(R + mg) = 0
⇒ T − μR − μ mg = 0
⇒ T − μ(Mg − T) − μmg = 0
T − μMg + μt − μmg = 0



⇒ T (1 + μ) = μMg + μmg

`=> "T" = (mu  ("M"+"m")"g")/(1+mu)`

Therefore, the maximum force exerted by the man is `(mu  ("M"+"m")"g")/(1+mu)`.

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Chapter 6: Friction - Exercise [Page 98]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 6 Friction
Exercise | Q 21 | Page 98

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