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Question
The general solution of the trigonometric equation tan2 θ = 1 is ____________
Options
`theta =npi+-(pi/3),n in z`
`theta =npi+-pi/6, n in z`
`theta=npi+-pi/4, n in z`
`0=npi, n in z`
Solution
`tan^2theta=1=tan^2(pi/4)`
`tan^2theta=tan^2 alpha => theta=npi+-alpha`
`therefore theta=npi+-pi/4`
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