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Question
The given figure shows a circle with centre O such that chord RS is parallel to chord QT, angle PRT = 20° and angle POQ = 100°. Calculate:
(iii) angle QRS
Solution
Join PQ, RQ and ST.
RS ∥ QT
∴ `∠`SRT = `∠`QTR (alternate angles)
But `∠`QTR = 40°
∴ `∠`SRT = 40°
Now,
`∠`QRS = `∠`QRP + `∠`PRT + `∠`SRT
⇒ `∠`QRS = 50° + 20° + 40° = 110°
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