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Question
The horizontal component of the earth's magnetic field at a place is `1/sqrt(3)` time the vertical component. Determine the angle of dip at that place.
Solution
Let angle of dip = θ, vertical component = V Tesla
∴ tan θ = `V/H = V/(1/sqrt(3)V)= sqrt(3) `= tan 60°
θ = 60°
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