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Question
The inverse of the function `"y" = (10^"x" - 10^-"x")/(10^"x" + 10^-"x")` is ____________.
Options
`"log"_10 (2 - "x")`
`1/2 "log"_10 ((1 + "x")/(1 - "x"))`
`1/2 "log"_10 (2"x" - 1)`
`1/4 "log" ((2"x")/(2 - "x"))`
MCQ
Fill in the Blanks
Solution
The inverse of the function `"y" = (10^"x" - 10^-"x")/(10^"x" + 10^-"x")` is `underline(1/2 "log"_10 ((1 + "x")/(1 - "x")))`.
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