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प्रश्न
The inverse of the function `"y" = (10^"x" - 10^-"x")/(10^"x" + 10^-"x")` is ____________.
विकल्प
`"log"_10 (2 - "x")`
`1/2 "log"_10 ((1 + "x")/(1 - "x"))`
`1/2 "log"_10 (2"x" - 1)`
`1/4 "log" ((2"x")/(2 - "x"))`
MCQ
रिक्त स्थान भरें
उत्तर
The inverse of the function `"y" = (10^"x" - 10^-"x")/(10^"x" + 10^-"x")` is `underline(1/2 "log"_10 ((1 + "x")/(1 - "x")))`.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
