Question

The length of a rectangle is three times its breadth. If its perimeter is 64 cm, find the sides of the rectangle

Answer 1

Given perimeter of a rectangle = 64 cm

Also given length is three times its breadth

Let the breadth of the rectangle = b cm

∴ Length = 3 × b cm

Perimeter = 64 m

i.e., 2 × (l + b) = 64 m

2 × (3b + b) = 64 m

2 × 4b = 64 m

4b = ${\displaystyle \frac{64}{2}}$ = 32 m

b = ${\displaystyle \frac{32}{4}}$ = 8 m

l = 3 × b

= 3 × 8

= 24 m

∴ Breadth of the rectangle = 8 m

Length of the rectangle = 24 m