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Question
The length of a second’s pendulum on the surface of the Earth is 0.9 m. The length of the same pendulum on the surface of planet X such that the acceleration of the planet X is n times greater than the Earth is
Options
0.9 n
`0.9/"n""m"`
0.9 n2m
`0.9/"n"^2`
Solution
0.9 n
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