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Question
The magnitude of surface tension of liquid depends on the attractive forces between the molecules. Arrange the following in increasing order of surface tension:
water, alcohol \[\ce{(C2H5OH)}\] and hexane \[\ce{[CH3(CH2)4CH3)]}\].
Solution
Water and alcohol are polar molecules which have high electronegative O atm so they have hydrogen bonding along with dipole-dipole interaction. Hexane is a nonpolar molecule that has London dispersion force which is a weak force between the molecules. Water has stronger H-bonding than alcohol. So, the order of attractive force will be:
Hexane < Alcohol < Water
More attractive forces between the molecules, the greater the magnitude of surface tension of the liquid.
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