Advertisements
Advertisements
Question
The number of unit cells in 8 gm of an element X (atomic mass 40) which crystallizes in bcc pattern is (NA is the Avogadro number)
Options
6.023 × 1023
6.023 × 1022
60.23 × 1023
`((6.023 xx 10^23)/(8 xx 40))`
Solution
6.023 × 1022
APPEARS IN
RELATED QUESTIONS
The vacant space in bcc lattice unit cell is ____________.
The fraction of total volume occupied by the atoms in a simple cubic is
If ‘a’ stands for the edge length of the cubic system; sc, bcc, and fcc. Then the ratio of radii of spheres in these systems will be respectively.
If ‘a’ is the length of the side of the cube, the distance between the body centered atom and one corner atom in the cube will be
Potassium has a bcc structure with nearest neighbor distance 4.52 A0. its atomic weight is 39. its density will be
What is the coordination number of atoms in a bcc structure?
An element has bcc structure with a cell edge of 288 pm. the density of the element is 7.2 g cm−3. how many atoms are present in 208 g of the element.
An atom crystallizes in fcc crystal lattice and has a density of 10 g cm−3 with unit cell edge length of 100 pm. calculate the number of atoms present in 1 g of crystal.
Atoms X and Y form bcc crystalline structure. Atom X is present at the corners of the cube and Y is at the centre of the cube. What is the formula of the compound?
Sodium metal crystallizes in bcc structure with the edge length of the unit cell 4.3 × 10−8 cm. calculate the radius of a sodium atom.