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Question
The numerical aperture of objective of a microscope is 0.12. The limit of resolution, when light of wavelength 6000A is used to view an object is.......................
- 0.25 * 10-7m
- 2.5 * 10-7m
- 25 * 10-7m
- 250 * 10-7m
Solution
(c) 25 * 10-7m
The minimum resolvable linear distance between two nearby objects is given by
`"x"=lambda/(2"NA")=(6000xx10^-10)/(2xx0.12)=2.5xx10^-6"m"=25xx10^-7"m"`
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Resolving Power of a Microscope and Telescope
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RELATED QUESTIONS
The resolving power of telescope of aperture 100 cm for light of wavelength 5.5 x 10-7 m is _______________.
If 'a' is the aperture of telescope and A. is the wavelength of light then resolving power of telescope is .............
a) `lambda/(1.22a)`
b) `(1.22a)/lambda`
c) `(1.22 lambda)/a`
d) `a/(1.22lambda)`
