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Question
If 'a' is the aperture of telescope and A. is the wavelength of light then resolving power of telescope is .............
a) `lambda/(1.22a)`
b) `(1.22a)/lambda`
c) `(1.22 lambda)/a`
d) `a/(1.22lambda)`
Solution
d) `a/(1.22lambda)`
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Resolving Power of a Microscope and Telescope
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