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The odds against a husband who is 60 years old, living till he is 85 are 7:5. The odds against his wife who is now 56, living till she is 81 are 5:3. Find the probability that exactly one of them wi - Mathematics and Statistics

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Question

The odds against a husband who is 60 years old, living till he is 85 are 7:5. The odds against his wife who is now 56, living till she is 81 are 5:3. Find the probability that exactly one of them will be alive 25 years hence

Sum

Solution

Let H ≡ the event that husband who is 60 is alive till age 85

W ≡ the event that wife who is 56 is alive till age 81

Odds against husband living till age 85 are 7:5

∴ P(H') = `7/(7 + 5) = 7/12`

∴ P(H) = 1 – P(H') = `5/12`

Odds against wife living till age 81 are 5:3

∴ P(W') = `5/(5 + 3) = 5/8`

∴ P(W) = 1 –  P(W') = `3/8`

The required event will happen if husband is alive and wife is dead or husband is dead and wife is alive

∴ the required probability = P[(H ∩ W') ∪ (H' ∩ W)]

= P(H ∩ W') + P(H' ∩ W)  ...[∵ events H ∩ W' and H' ∩ W are mutually exclusive]

= P(H) · P(W') + P(H') · P(W)  ...[∵ events are independent]

= `5/12*5/8 + 7/12* 3/8`

= `46/96`

= `23/48`

shaalaa.com
Odds (Ratio of Two Complementary Probabilities)
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Chapter 9: Probability - Exercise 9.5 [Page 211]

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