Advertisements
Advertisements
Question
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
Options
The oxidation number of hydrogen is always +1.
The algebraic sum of all the oxidation numbers in a compound is zero.
An element in the free or the uncombined state bears oxidation number zero.
In all its compounds, the oxidation number of fluorine is – 1.
Solution
The oxidation number of hydrogen is always +1.
Explanation:
Oxidation number of hydrogen is – 1 in metal hydrides like \[\ce{NaH}\].
APPEARS IN
RELATED QUESTIONS
Assign oxidation numbers to the underlined element in the following species:
H4P2O7
Assign oxidation numbers to the underlined elements in the following species:
K2MnO4
Assign oxidation numbers to the underlined elements in the following species:
CaO2
Assign oxidation numbers to the underlined elements in the following species:
NaBH4
Assign oxidation numbers to the underlined elements in the following species:
KAl(SO4)2.12 H2O
What is the oxidation numbers of the underlined elements in the following and how do you rationalise your results?
Fe3O4
The reaction \[\ce{Cl2 (g) + 2OH- (aq) -> ClO- (aq) + Cl- (aq) + H2O (l)}\] represents the process of bleaching. Identify and name the species that bleaches the substances due to its oxidising action.
\[\ce{PbO}\] and \[\ce{PbO2}\] react with \[\ce{HCl}] according to following chemical equations:
\[\ce{2PbO + 4HCl -> 2PbCl2 + 2H2O}\]
\[\ce{PbO2 + 4HCl -> PbCl2 + Cl2 + 2H2O}\]
Why do these compounds differ in their reactivity?
In order to oxidise a mixture of one mole of each of \[\ce{FeC2O4, Fe2(C2O4)3, FeSO4 and Fe2(SO4)3}\] in acidic medium, the number of moles of KMnO4 required is ______.
On reaction with a stronger oxidizing agent like KIO4, hydrogen peroxide with the evolution of O2. The oxidation number of I in KIO4 changes to ______.