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Question
The power of a lens ‘X’ is −2.5 D. Name the lens and determine its focal length in cm. For which eye defect of vision will an optician prescribe this type of lens as a corrective lens?
Numerical
Solution
Given: P = −2.5 D (diopters)
Formula:
Determine the focal length,
The power P of a lens is related to its focal length f (in meters) by the equation:
∴ `P = 1/f`
∴ `f = 1/2.5`
= −0.4 m
= −40 cm (or 40 cm in magnitude)
The negative sign of the power indicates that the lens is a diverging (concave) lens.
A concave lens is typically prescribed to correct myopia (nearsightedness). In myopia, the eye focuses images in front of the retina. A concave lens diverges the incoming light rays, moving the focal point back onto the retina for clear vision.
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