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Question
The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages
Solution
Let present age of son = x year
Then age of his father = 2x
8 years hence,
Age of son = (x + 8) years and age of father = (2x + 8) years
According to the condition,
`(2"x" + 8)/("x" + 8) = 7/4`
⇒ 8x + 32 = 7x + 56
⇒ 8x – 7x = 56 – 32
⇒ x = 24
Present age of son = 24 years
and age of father = 2x = 2 x 24 = 48 years
Hence age of man = 48 years and age of his son = 24 years
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