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Question
The pressure of water on the ground floor is 40,000 Pa and on the first floor is 10,000 Pa. Find the height of the first floor. (Take : density of water = 1000 kg m-3, g = 10 m s-2)
Solution
Pressure of water on ground floor = 40,000 pascal
Pressure of water on first floor = 10,000 pascal
Density of water , ρ = 1000 kg m-3
Acceleration due to gravity , g = 10 ms-2
Let h be the height of the first floor.
Difference in water pressure between ground and first floor = hρg
or , (40,000 - 10,000) = h (1000) (10)
or , h = 3 m
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