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The probability distribution of a random variable X is: X 0 1 2 3 4 P(X) 0.1 k 2k k 0.1 where k is some unknown constant. The probability that the random variable X takes the value 2 is: - Mathematics

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Question

The probability distribution of a random variable X is:

X 0 1 2 3 4
P(X) 0.1 k 2k k 0.1

where k is some unknown constant.

The probability that the random variable X takes the value 2 is ______.

Options

  • `1/5`

  • `2/5`

  • `4/5`

  • 1

MCQ
Fill in the Blanks

Solution

The probability that the random variable X takes the value 2 is `underlinebb(2/5)`.

Explanation:

We have 

P(0) + P(1) + P(2) + P(3) + P(4) = 1

0.1 + k + 2k + k + 0.1 = 1

0.2 + 4k = 1

4k = 0.8

k = 0.2 = `1/5`

Given P(2) = 2k

`= 2xx1/5 = 2/5`

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