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Question
The probability of happening of an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then find the probability of neither A nor B happen
Solution
Here P(A) = 0.5, P(B) = 0.3
P(A ∪ B) = P(A) + P(B) ...[A and B are mutually exclusive]
= 0.5 + 0.3
= 0.8
Probability of neither A nor B = [P(A ∪ B)']
= 1 – P(A ∪ B)
= 1 – 0.8
= 0.2
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