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Question
The probability that atleast one of A and B occur is 0.6. If A and B occur simultaneously with probability 0.2, then find `"P"(bar"A") + "P"(bar"B")`
Solution
Here P(A ∪ B) = 0.6, P(A ∩ B) = 0.2
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
0.6 = P(A) + P(B) – 0.2
P(A) + P(B) = 0.8
`"P"(bar"A") + "P"(bar"B")` = 1 – P(A) + 1 – P(B)
= 2 – [P(A) + P(B)]
= 2 – 0.8
= 1.2
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