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Question
The radii of the circular ends of a frustum of height 6 cm are 14 cm and 6 cm, respectively. Find the slant height of the frustum.
Solution
We have,
Height of the frustum, h = 6 cm,
Radii of the circular ends, R = 14 cm and r = 6 cm
Let the slant height of the frustum be l.
Now,
`"l" = sqrt(("R"- "r")^2 + "h"^2)`
`=sqrt((14-6)^2+6^2)`
`=sqrt(8^2 + 6^2)`
`=sqrt(64+36)`
`=sqrt(100)`
= 10 cm
so, the slant height of the frustum is 10 cm.
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Find the total surface area of frustum, if its radii are 15 cm and 7 cm. Also, the slant height of the frustum is 14 cm.
Radii of the frustum = `square` cm and `square` cm
Slant height of the frustum = `square` cm
Total surface area = `π[(r_1^2 + r_2^2 + (r_1 + r_2)l]`
= `22/7 [square + square + (square + square) square]`
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