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Question
The radii of the ends of a bucket 16 cm height are 20 cm and 8 cm. The curved surface area of the bucket is
Options
1760 cm2
2240 cm2
880 cm2
3120 cm2
Solution
Radius of top of bucket r1 = 20 cm
Radius of bottom of bucket r2 = 8 cm
Height of bucket = 16 cm
The curved surface area of bucket `= pi (r_1 +r_2) l`
`l = sqrt(h^2 + (r_1 +r_2)^2)`
`= sqrt(16^2 + (20 - 8)^2)`
`=sqrt(256 + 144)`
`l = sqrt400`
`l = 20 "cm"`
C.S.A. of bucket
` = pi (20 + 8) xx 20`
`= 22/7 xx 28 xx 20`
`=22 xx 80`
= \[1760 \ cm^2\]
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