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The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is ______. - Physics

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Question

The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is ______.

Options

  • 1.01 × 10–11m

  • 1.59 × 10–10m

  • 2.12 × 10–10m

  • 4.77 × 10–10m

MCQ
Fill in the Blanks

Solution

The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is `underline(bb(4.77 xx 10^-10 m))`.

Explanation:

The radius of an atom whose principal quantum number is n is given by r = n2r0

Where r0 = radius of innermost electron orbit for hydrogen atom and r0 = 5.3 × 10–11m

For the second excited state, n = 3

∴ r = 32 × r0

= 9 × 5.3 × 10–11

r = 4.77 × 10–10m.

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