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Tamil Nadu Board of Secondary EducationHSC Science Class 12

The solenoids S1 and S2 are wound on an iron-core of relative permeability 900. The area of their cross-section and their length are the same and are 4 cm2 and 0.04 m, respectively. - Physics

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Question

The solenoids S1 and S2 are wound on an iron-core of relative permeability 900. The area of their cross-section and their length are the same and are 4 cm2 and 0.04 m, respectively. If the number of turns in S1 is 200 and that in S2 is 800, calculate the mutual inductance between the coils. The current in solenoid 1 is increased from 2A to 8A in 0.04 second. Calculate the induced emf in solenoid 2.

Numerical

Solution

Given data:

μr = 900

A2 = 4 × 10-4 m2

l = 0.04 m

n1 = 5000

n2 = 20,000

i1 =2A to i2 = 8A

dt = 0.048

M = ?

ε2 = ?

M = μ0 μr n1 n2 A2 l

M = 4π × 10-7 × 900 × 5000 × 20000 × 4 × 10-4 ×0.04

M = 4π × 90 × 4 × 4 × 10-4

M = 18086 × 10-4H

M = 1.81 H

induced emf,

ε2 = M `"di"/"dt"`

ε2 = `1.81 ((8 - 2)/0.04)`

ε2 = `(1.81 xx 6)/(4 xx 106-2)`

= 2.715 × 10-2 V

ε2 = 271.5 V

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Chapter 4: Electromagnetic Induction And Alternating Current - Evaluation [Page 262]

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Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 4 Electromagnetic Induction And Alternating Current
Evaluation | Q IV. 16. | Page 262
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