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The solution of the equation ax + by + 5 = 0 and bx − ay − 12 = 0 is (2, – 3). Find the values of a and b - Algebra

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Question

The solution of the equation ax + by + 5 = 0 and bx − ay − 12 = 0 is (2, – 3). Find the values of a and b

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Solution

Since (2, – 3) is the solution of ax + by + 5 = 0 and bx – ay – 12 = 0, the point (x, y) = (2, – 3) satisfies the given equations.

ax + by + 5 = 0

∴ ax + by = – 5    ......(i)

bx – ay – 12 = 0

∴ bx – ay = 12     ......(ii)

Putting x = 2 and y = – 3 in equations (i) and (ii), we get

2a – 3b = – 5     ......(iii)

2b + 3a = 12

i.e., 3a + 2b = 12  ......(iv)

Multiplying equation (iii) by 2, we get

4a – 6b = – 10   .......(v)

Multiplying equation (iv) by 3, we get

9a + 6b = 36    .......(vi)

Adding equations (v) and (vi), we get

    4a – 6b = –10
+ 9a + 6b = 36   
   13a        = 26

∴ a = `26/13` = 2

Substituting a = 2 in equation (iv), we get

3(2) + 2b = 12

∴ 6 + 2b = 12

∴ 2b = 6

∴ b = `6/2` = 3

∴ a = 2 and b = 3

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Chapter 1: Linear Equations in Two Variables - Q.3 (B)

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SCERT Maharashtra Algebra (Mathematics 1) [English] 10 Standard SSC
Chapter 1 Linear Equations in Two Variables
Q.3 (B) | Q 9
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