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Question
A person starts a job with a fixed salary and yearly increment. After 4 years his salary is ₹ 15000 and after 10 years it becomes ₹ 18000. Then find his monthly salary and increment
Solution
Let the fixed salary be ₹ x and the annual increment be ₹ y.
Then, salary after 4 years = x + 4y
salary after 10 years = x + 10y
According to the first condition,
x + 4y = 15000 ......(i)
According to the second condition:
x + 10y = 18000 ......(ii)
Subtracting equation (i) from (ii), we get
x + 10y = 18000
- x + 4y = 15000
− − −____
6y = 3000
∴ y = `3000/6` = 500
Substituting y = 500 in equation (i), we get
x + 4(500) = 15000
∴ x + 2000 = 15000
∴ x = 13000
∴ The monthly salary is ₹ 13,000 and yearly increment is ₹ 500.
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