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Question
Solve the following systems of equations:
11x + 15y + 23 = 0
7x – 2y – 20 = 0
Solution
The given system of equation is
11x + 15y + 23 = 0 .........(i)
7x - 2y - 20 = 0 ...(ii)
From (ii), we get
2y = 7x - 20
`=> y = (7x - 20)/2`
Substituting y = `(70x - 20)/2` in (i) we get
`11x + 15((7x - 20)/2) + 23 = 0`
`=> 11x + (105x - 300)/2 + 23 = 0`
`=> (22x + 105x - 300 + 46)/2 = 0`
`=> 127x - 254 = 0`
=> 127x = 254
`> x = 254/127 = 2`
Putting 2 x = 2 in y = `(7x - 20)/2` we get
`=> y = (7xx2-20)/2`
`= (14-20)/2`
`= -6/2`
= -3
Hence, the solution of the given system of equations is x = 2, y = -3
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