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The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively ______. - Mathematics

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Question

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively ______.

Options

  • 4 and 24

  • 5 and 30

  • 6 and 36

  • 3 and 24

MCQ
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Solution

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively 6 and 36.

Explanation:

Let the present age of father is x year and the present age of son is y year.

(x + 4) = 4(y + 4)

⇒ x – 4y = 12  .......(i)

and x = 6y  .......(ii)

Substituting the value of x from (ii) in (i)

We get 2y = 12

⇒ y = 6

When y = 6,

Then from (ii),

x = 36

Hence present age of father is 36 year and age of son is 6 year.

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Chapter 3: Pair of Liner Equation in Two Variable - Exercise 3.1 [Page 19]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 3 Pair of Liner Equation in Two Variable
Exercise 3.1 | Q 13 | Page 19
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