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The Sum of the Ages of a Father and His Son is 45 Years. Five Years Ago, the Product of Their Ages Was 124. Determine Their Present Ages. - Mathematics

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Question

The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Determine their present ages.

Sum

Solution

Let the present age of the man be M years and his son's age be 5 years. Then, as per the question description, 

M + 5 = 45 ...... (i) 

{M - 5)(5 - 5) = 124 ...... (ii) 

From (i), we get: M=45-5 ...... (iii) 

Putting (iii) in (ii), we get: {45 - 5 - 5) (5 - 5) = 124 

⇒  (40 - 5)(5 - 5) =124

⇒ S2 - 45 S + 324 = 0

⇒ S2 - 9S - 36S + 324 = 0

⇒ S (5 - 9) - 36(5 - 9) = 0 

⇒ S = 9 , 36

⇒ S = 9 years and  hence , M = 36 years

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Chapter 7: Problems Based On Quadratic Equations - Exercise 7.1

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Frank Mathematics - Part 2 [English] Class 10 ICSE
Chapter 7 Problems Based On Quadratic Equations
Exercise 7.1 | Q 19
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