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The Sum of the Ages of a Father and His Son is 45 Years. Five Years Ago, the Product of Their Ages Was 124. Determine Their Present Ages. - Mathematics

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प्रश्न

The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Determine their present ages.

योग

उत्तर

Let the present age of the man be M years and his son's age be 5 years. Then, as per the question description, 

M + 5 = 45 ...... (i) 

{M - 5)(5 - 5) = 124 ...... (ii) 

From (i), we get: M=45-5 ...... (iii) 

Putting (iii) in (ii), we get: {45 - 5 - 5) (5 - 5) = 124 

⇒  (40 - 5)(5 - 5) =124

⇒ S2 - 45 S + 324 = 0

⇒ S2 - 9S - 36S + 324 = 0

⇒ S (5 - 9) - 36(5 - 9) = 0 

⇒ S = 9 , 36

⇒ S = 9 years and  hence , M = 36 years

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अध्याय 7: Problems Based On Quadratic Equations - Exercise 7.1

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 7 Problems Based On Quadratic Equations
Exercise 7.1 | Q 19
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