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Three Years Ago, a Man Was 5 Times the Age of His Son. Four Years Hence, He Will Be Thrice His Son'S Age. Find the Present Ages of the Man and His Son. - Mathematics

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प्रश्न

Three years ago, a man was 5 times the age of his son. Four years hence, he will be thrice his son's age. Find the present ages of the man and his son.

योग

उत्तर

Let the present age of the man be M years and his sons age be S years. 

Then, as per the question description, 

M - 3 = 5 (S-3 ) ...... (i) 

M + 4 =3 (S+4 ) ...... (ii) 

From (i), we get: M + 12 = 5 S 

⇒ S = `("M" + 12)/5`  .........(iii)

From (ii), we get: M - 8 = 3S

Putting (iii) above, we get: M - 8 = `(3 (M + 12))/5`

⇒ 5M - 40 = 3M + 36 

⇒  2M = 76 

⇒ M =38 years and hence,  S= 10 years 

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अध्याय 7: Problems Based On Quadratic Equations - Exercise 7.1

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 7 Problems Based On Quadratic Equations
Exercise 7.1 | Q 18
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