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Question
The sum of the first 12 terms of an A.P. is 900. If its first term is 20, then find the common difference and 12th term.
Sum
Solution
Given, a = 20, and the sum of 12 and the term is 900.
Using the formulas for the sum of n terms of an A.P.
Sn = `n/2 [2a + (n − 1) d]`
S12 = `12/2 [2 xx 20 + (12 − 1) d]`
900 = 6 [40 + 11d]
900 = 240 + 66d
66d = 900 − 240
66d = 660
d = `660/66`
∴ d = 10
Using the formula for the nth term to find a12.
an = a + (n − 1) d
a12 = 20 + (12 − 1) × 10
= 20 + 110
= 130
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