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The sum of the first 12 terms of an A.P. is 900. If its first term is 20, then find the common difference and 12th term. - Mathematics

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Question

The sum of the first 12 terms of an A.P. is 900. If its first term is 20, then find the common difference and 12th term.

Sum

Solution

Given, a = 20, and the sum of 12 and the term is 900.

Using the formulas for the sum of n terms of an A.P.

Sn = `n/2 [2a + (n − 1) d]`

S12 = `12/2 [2 xx 20 + (12 − 1) d]`

900 = 6 [40 + 11d]

900 = 240 + 66d

66d = 900 − 240

66d = 660

d = `660/66`

∴ d = 10

Using the formula for the nth term to find a12.

an = a + (n − 1) d

a12 = 20 + (12 − 1) × 10

= 20 + 110

= 130

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