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Question
The system of linear equations
5x + ky = 5,
3x + 3y = 5;
will be consistent if
Options
k ≠ – 3
k = –5
k = 5
k ≠ 5
MCQ
Solution
k ≠ 5
Explanation:
We have, 5x + ky – 5 = 0
And 3x + 3y – 5 = 0
For consistent system
`5/3 ≠ k/3`
`\implies` k ≠ 5
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