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Question
The total number of lions and peacocks in a certain zoo is 50. The total number of their legs is 140. Then find the number of lions and peacocks in the zoo.
Solution
Let the number of lions be x and the number of peacocks be y.
The total number of lions and peacocks in a certain zoo is 50.
So, x + y = 50 ...(I)
The total number of their legs is 140.
Lion has 4 legs while peacock has 2.
4x + 2y = 140
⇒ 2x + y = 70 ...(II)
Subtracting (I) from (II) we have
x + y = 50
2x + y = 70
− − −
−x = −20
∴ x = 20
Putting x = 20 in equation (I)
20 + y = 50
y = 50 - 20
y = 30
Thus, the number of lions = 20 and the number of peacocks = 30.
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