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Question
Sanjay gets fixed monthly income. Every year there is a certain increment in his salary. After 4 years, his monthly salary was Rs. 4500 and after 10 years his monthly salary became 5400 rupees, then find his original salary and yearly increment.
Solution
Let the fixed monthly income be Rs x.
Annual increment be Rs y.
After 4 years, his monthly salary was Rs. 4500
Monthly salary + annual increment of 4 years = 4500
x + 4y = 4500 ...(I)
After 10 years his monthly salary became 5400 rupees
Monthly salary + annual increment of 10 years = 5400
x + 10y = 5400 ...(II)
Subtracting I from II
x + 4y = 4500
x + 10y = 5400
− − −
−6y = −900
∴ y = 150
put y = 150 in equation (I)
x + 4y = 4500
x + 4 × 150 = 4500
x + 600 = 4500
x = 4500 - 600
x = 3900
Thus, the monthly salary = Rs. 3900
Annual increment = Rs.150
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