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Question
The value of (7–1 – 8–1) –1 – (3–1 – 4–1) –1 is ______.
Options
44
56
68
12
Solution
The value of (7–1 – 8–1) –1 – (3–1 – 4–1) –1 is 44.
Explanation:
Using law of exponents, `a^-m = 1/a^m` ...[∵ A is non-zero integer]
∴ `(7^-1 - 8^-1)^-1 - (3^-1 - 4^-1)^-1 = (1/7 - 1/8)^-1 - (1/3 - 1/4)^-1`
= `(1/56)^-1 - (1/12)^-1`
= 56 – 12
= 44
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