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Question
The value of \[\ce{K_c}\] for the reaction \[\ce{2HI (g) ⇌ H2 (g) + I2 (g)}\] is 1 × 10–4 At a given time, the composition of reaction mixture is \[\ce{[HI]}\] = 2 × 10–5 mol, \[\ce{[HI]}\] = 1 × 10–5 mol and \[\ce{[I2]}\] = 1 × 10–5 mol In which direction will the reaction proceed?
Solution
At a given time the reaction quotient Q for the reaction will be given by the expression.
`Q = ([H_2][I_2])/([HI]^2)`
= `(1 xx 10^-5 xx 1 xx 10^-5)/(2 xx 10^-5)^2 = 1/4`
= 0.25 = 2.5 × 10–1
As the value of reaction quotient is greater than the value of Kc i.e. 1 × 10–4 the reaction will proceed in the reverse direction.
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