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Question
The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 105 ms–1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.
Solution
According to de Broglie’s expression,
`lambda = "h"/("mv")`
Substituting the values in the expression,
`lambda = (6.626xx10^(-34)" Js")/((0.1 " kg")(4.37xx10^5 " ms"^(-1))`
`lambda = 1.516 xx 10^(38) " m"`
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