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Question
The weight of coffee in 70 packets are shown in the following table:
| Weight (in g) | Number of packets |
| 200 – 201 | 12 |
| 201 – 202 | 26 |
| 202 – 203 | 20 |
| 203 – 204 | 9 |
| 204 – 205 | 2 |
| 205 – 206 | 1 |
Determine the modal weight.
Solution
In the given data, the highest frequency is 26, which lies in the interval 201 – 202
Here, l = 201, fm = 26, f1 = 12, f2 = 20 and (class width) h = 1
∴ Mode = `l + ((f_m - f_1)/(2f_m - f_1 - f_2)) xx h`
= `201 + ((26 - 12)/(2 xx 26 - 12 - 20)) xx 1`
= `201 + (14/(52 - 32))`
= `201 + 14/20`
= 201 + 0.7
= 201.7 g
Hence, the modal weight is 201.7 g.
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