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Question
There are 25 tickets numbered 1, 2, 3, 4,..., 25 respectively. One ticket is draw at random. What is the probability that the number on the ticket is a multiple of 3 or 5?
Options
`2/5`
`11/25`
`12/25`
`13/25`
Solution
`12/25`
Explanation:
Total number of tickets = 25
Let E be the event of getting a multiple of 3 or 5.
Then,
Multiples of 3 are 3, 6, 9, 12, 15, 18, 21 and 24.
Multiples of 5 are 5, 10, 15, 20 and 25.
Number of favourable outcomes = ( 8 + 5 − 1) = 12
∴ P (getting a multiple of 3 or 5 ) = P (E) = `12/25`
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