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There is a Continuous Growth in Population of a Village at the Rate of 5% per Annum. If Its Present Population is 9,261, What Population Was 3 Years Ago? - Mathematics

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Question

There is a continuous growth in population of a village at the rate of 5% per annum. If its present population is 9,261, what population was 3 years ago?

Sum

Solution

Let P be the population 3 years ago.
Then, present population = P x `(1 + 5/100)^3`

∴ 9,261 = `("P" xx (21)/(20) xx (21)/(20) xx (21)/(20))`

or P = `(9,261 xx (20)/(21) xx (20)/(21) xx (20)/(21))`

= 8,000

Hence, 3years ago the population of village was = 8,000.

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Concept of Compound Interest - Compound Interest as a Repeated Simple Interest Computation with a Growing Principal
  Is there an error in this question or solution?
Chapter 1: Compound Interest - Exercise 1

APPEARS IN

ICSE Mathematics [English] Class 10
Chapter 1 Compound Interest
Exercise 1 | Q 5

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