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Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarized as follows. Fine the mean heartbeats per minute for these women, choosing a - Mathematics

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Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarized as follows. Fine the mean heartbeats per minute for these women, choosing a suitable method.

Number of heartbeats per minute 65 - 68 68 - 71 71 - 74 74 - 77 77 - 80 80 - 83 83 - 86
Number of women 2 4 3 8 7 4 2
Sum

Solution

To find the class mark of each interval (xi), the following relation is used:

`x_i  = ("Upper class limit + Lower class limit")/2`

Class size, h, of this data = 3

Taking 75.5 as the assumed mean (a), di, ui, fiui are calculated as follows.

Number of heart beats per minute

Number of women fi

xi di = xi − 75.5 `u_i = (x_i-75.5)/3` fiui
65 − 68 2 66.5 − 9 -3 -6
68 − 71 4 69.5 − 6 -2 -8
71 − 74 3 72.5 − 3 -1 -3
74 − 77 8 75.5 0 0 0
77 − 80 7 78.5 3 1 7
80 − 83  4 81.5 6 2 8
83 − 86 2 84.5 9 3 6
Total 30       4

From the table, we obtain

`sumf_i = 30`

`sumf_iu_i = 4`

mean `barx=a+((sumf_iu_i)/(sumf_i))xxh`

`= 75.5 +(4/30) xx 3`

= 75.5 + 0.4 = 75.9

Therefore, the mean beats per minute for these women are 75.9 beats per minute.

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Chapter 14: Statistics - Exercise 14.1 [Page 271]

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NCERT Mathematics [English] Class 10
Chapter 14 Statistics
Exercise 14.1 | Q 4 | Page 271
RD Sharma Mathematics [English] Class 10
Chapter 15 Statistics
Exercise 15.3 | Q 4 | Page 22

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