Advertisements
Advertisements
Question
Three consecutive integers add up to 51. What are these integers?
Solution
Let three consecutive integers be x, x + 1, and x + 2.
Sum of these numbers = x+ x + 1 + x + 2 = 51
3x + 3 = 51
On transposing 3 to R.H.S, we obtain
3x = 51 − 3
3x = 48
On dividing both sides by 3, we obtain
`(3x)/3 = 48/3`
x = 16
x + 1 = 17
x + 2 = 18
Hence, the consecutive integers are 16, 17, and 18
APPEARS IN
RELATED QUESTIONS
Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
The number of boys and girls in a class are in the ratio 7:5. The number of boys is 8 more than the number of girls. What is the total class strength?
Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?
What should be added to twice the rational number `(-7)/3 "to get" 3/7`?
3 years ago, the age of a boy was y years. His age 2 years ago was (y – 2) years.
Shikha’s present age is p years. Reemu’s present age is 4 times the present age of Shikha. After 5 years Reemu’s age will be 15p years.
Rs. 13500 are to be distributed among Salma, Kiran and Jenifer in such a way that Salma gets Rs. 1000 more than Kiran and Jenifer gets Rs. 500 more than Kiran. Find the money received by Jenifer.
The sum of three consecutive even natural numbers is 48. Find the greatest of these numbers.
Kusum buys some chocolates at the rate of Rs. 10 per chocolate. She also buys an equal number of candies at the rate of Rs. 5 per candy. She makes a 20% profit on chocolates and 8% profit on candies. At the end of the day, all chocolates and candies are sold out and her profit is Rs. 240. Find the number of chocolates purchased.
