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Baichung’S Father is 26 Years Younger than Baichung’S Grandfather and 29 Years Older than Baichung. the Sum of the Ages of All the Three is 135 Years. What is the Age of Each One of Them? - Mathematics

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Question

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Solution

Let Baichung’s father’s age be x years. Therefore, Baichung’s age and Baichung’s grandfather’s age will be (x − 29) years and (x + 26) years respectively.

According to the given question, the sum of the ages of these 3 people is 135 years.

∴ x + x − 29 + x + 26 = 135

3x − 3 = 135

On transposing 3 to R.H.S, we obtain

3x = 135 + 3

3x = 138

On dividing both sides by 3, we obtain

`(3x)/3 = 138/3`

x = 46

Baichung’s father’s age = x years = 46 years

Baichung’s age = (x − 29) years = (46 − 29) years = 17 years

Baichung’s grandfather’s age = (x + 26) years = (46 + 26) years = 72 years

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Chapter 2: Linear Equations in One Variable - Exercise 2.2 [Page 28]

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NCERT Mathematics [English] Class 8
Chapter 2 Linear Equations in One Variable
Exercise 2.2 | Q 11 | Page 28
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