Advertisements
Advertisements
Question
Three resistors of 6Ω, 3Ω and 2Ω are connected together so that their total resistance is greater than 6Ω but less than 8Ω Draw a diagram to show this arrangement and calculate its total resistance.
Solution
We connect the resistance of 3 Ω and 2 Ω in parallel to each other and then connect this (parallel combination) to the 6 Ω resistance in series. The required arrangement is as shown in given figure. The equivalent resistance of 3Ω and 2 Ω in parallel.
`1/"R" = 1/3 + 1/2 = (2 + 3)/6 = 5/6`
or R = `6/5`Ω = 1.2 Ω
Thus, the total resistance of the set up is (1.2 + 6) Ω = 7.2 Ω
APPEARS IN
RELATED QUESTIONS
Find the equivalent resistance between points A and B
Name the material which is the best conductor of electricity.
Calculate the resistance of an aluminium cable of length 10 km and diameter 2.0 mm if the resistivity of aluminium is 27 × 10−8 Ωm.
Give the law of combination of resistances in series.
V = IRTwo resistances X and Y are connected turn by turn : (i) in parallel, and (ii) series. In which case the resultant resistance will be less than either of the individual resistances?R = R1+ R2+ R3
Name the material of wire used for making standard resistances. Give a reason.
State the effect of rise in temperature on the resistance of semi-conductors.
Two lamps of resistance 30Ω and 20Ω respectively are connected in series in a 110V circuit. Calculate:
(i) the total resistance in the circuit
(ii) the current in the circuit, and
(iii) the voltage drop across each lamp.
