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To carry out the so-called "electrolysis of water", sulphuric acid is added to water. How does the addition of sulphuric acid produce a conducting solution? - Chemistry

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Question

To carry out the so-called "electrolysis of water", sulphuric acid is added to water. How does the addition of sulphuric acid produce a conducting solution?

Answer in Brief

Solution 1

When sulphuric acid is added to water, it becomes a good conductor, as the addition of sulphuric acid causes the dissociation of water molecules into H+ and OH ions, which are responsible for the conduction of electricity by pure water. The water thus obtained is called acidified water.

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Solution 2

Pure water is non-electrolyte. All of it is made up of molecules. An electrolyte is added with a small quantity of sulphuric acid, causing the solution to ionise, giving the ions \[\ce{SO^2-_4}\] and H+. Thus, water was added with a small quantity of sulphuric acid containing the positive H+ ions and the negative \[\ce{SO^2-_4}\] and OH− ions as follows:

\[\ce{H2O <=> H+ + OH-}\]

\[\ce{H2SO4 -> 2H+ + SO^2-_4}\]

Thus, the addition of H2SO4 helps in the ionisation of water.

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Notes

Students can refer to the provided solutions based on their preferred marks.

Examples of Electrolysis - Electrolysis of Acidified Water Using Platinum Electrodes
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Chapter 6: Electrolysis - Exercise 4 [Page 148]

APPEARS IN

Frank Chemistry - Part 2 [English] Class 10 ICSE
Chapter 6 Electrolysis
Exercise 4 | Q 9 | Page 148
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